🏄 Welcome to QSD's House of Wonders ! 🔮 欢迎来到QSD妙妙屋 ! 👨‍⚖️ QSD&QSB wish you a spectacular day! 🛡️ House of QSD: Mors potius quam tædium 🗺️ Here's a page for you 👉 Voyage ✨ S·P·Q·R ! 🐈 欢迎来到QSD妙妙屋 ! 🤷‍♂️ Who the hell is QSD ??? 🫵🏻 Maybe you are QSD ! 🥂 Welcome to QSB's House of Wonders ! 🪦 The foundation of this site: Day One · The Epitaph . 🍭 Do you know QSD are once known as QXD ?

NOTICE BOARD

🖥️ QSD and his friends welcome you to enjoy this site on a laptop, in particular Chrome and Safari.

🌗There may or may not be some Tarot cards hidden at the lower corners [laptop only]. As a hint, This page's lower left corner leads to QSD's rolling 7-day favourite voyage, and lower right to ...?

➡️➡️➡️ QSD减肥进行时 🏃‍♂️💨💨… !
Attempt #8 von 27.10.2025

What’s New!

“有哪些文件夹刚刚被新建了呢？“

A Bizzard Self-Intro…?

• 🤖QSDQSB
• 🔬24’ Maths&Stats at Ox
• 🦃From The Queen’s College, whose logo consists of three turkeys
• ☕️Americano addict
  • ⬆️Might trigger something if you click the coffee emoji
• 📷Photography rookie
• 🎸Amateur music composer
  • 🎹This guy really used to know piano, but not anymore
  • 🎻Proudly self-claim to be learning violin
  • 🎺So-called 网易音乐人
• 📱WeChat $\times\times\times\times\times\times$; Would argue reasonably straightforward to guess based on this site.
• 🎮Civilization VI! But suck at it :(
• 🧱Lego 76042+71043+21327
• ⚠️The previous red brick has nothing to do with Keble College.
• 🧙‍♂️𝕽𝖆𝖛𝖊𝖓𝖈𝖑𝖆𝖜🦅
• 🕶S.H.I.E.L.D. agent
• 📺💷YPM! 💻Silicon Valley! 🧑‍💼Better Call Saul! 👸🏼Disenchantment! 🤖Westworld S1-2! 🐉Game of Thrones S1-4!
• 👾Emoji crusher(as you can see from this page)
• 🎨马卡龙色系yyds
• 🐱骨灰级猫猫粉
• 🐟enjoy 摸鱼 every day
• 🏃努力减肥中(但愿)
• 🪷Geographically Hangzhounese, spiritually Shanghainese

What else should we do before publishing this page?

Test latex: \(\small\forall x \in \mathbb{R}, \exists \,\varepsilon >0 \,\,s.t.\)

That was too easy, let’s try:

Argument Principle

Suppose that $U$ is an open set and $f: U \rightarrow$ $\mathbb{C}$ is a meromorphic function on $U$. If $B(a, r) \subseteq U$ and $N$ is the number of zeros (counted with multiplicity) and $P$ is the number of poles (again counted with multiplicity) of $f$ inside $B(a, r)$ and $f$ has neither on $\partial B(a, r)$ then \(N-P=\frac{1}{2 \pi i} \int_{\gamma} \frac{f^{\prime}(z)}{f(z)} d z,\) where $\gamma(t)=a+r e^{2 \pi i t}$ is a path with image $\partial B(a, r)$. Moreover this is the winding number of the path $\Gamma=f \circ \gamma$ about the origin.

Don’t know what this is? It’s quite simple, just get a maths degree and you will see.

Something Utterly Ludicrous

Consider a language that doesn’t support the logic not, 13 years after someone pointing out: The Mighty Liquid